Version: v0.7.0 - Beta.  We welcome contributors & feedback.

UrlQuery.getAll

getAll($mapOfParams) -> map

Description

Get a map of URL params, filtered by the given validation rules.

$query = url'/page?name=test&num=123'.getQuery()

$query.getAll({
    name: 'username',
    num: 'i',
})

//= { name: 'test', num: 123 }

See Also